Three numbers are in Arithmetic Progression (AP) whose sum is 30 and the product is 910. Then the greatest number in the AP is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 13
Let the numbers in AP be a - d, a, a + d
a - d + a + a + d = 30
⇒ 3a = 30
⇒ a = 10
Also
(a - d)(a)(a + d) = 910
⇒ (10 - d)(10)(10 + d) = 910
⇒ 100 - d2 = 91
⇒ d = 3 or -3
Thus, the number are 7, 10 and 13 or 13, 10, 7.
Hence, the greatest no is 13.