SSC CHSL 2024 PYQ — Question 71

SSC CHSL - 11 July 2024 - Shift 2 • Quantitative Aptitude • Q71

Three cubes each of side 5 cm are joined end to end. The surface area of the resulting cuboid is:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 350 cm2.

We have three cubes, each side 5 cm, joined end to end to form a cuboid

So, length(l) = 3 × 5 = 15 cm

Breadth(b) = 5 cm

Height(h) = 5 cm

The surface area of a cuboid(SA) = 2(lb + bh + hl)

⇒ SA = 2(15 × 5 + 5 × 5 + 5 × 15)

⇒ SA = 2(75 + 25 + 75)

⇒ SA = 2 × 175 = 350 cm2