There are two pipes used to fill a tank and when operated together, they can fill the tank in 20 minutes. If one pipe can fill the tank two and a half times as quickly as the other, then the faster pipe alone can fill the tank in:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 28 min.
Given that, time taken by two pipes together = 20 minutes
Efficiency of faster pipe = times efficiency of slower pipe
Let the efficiency of slower pipe be x units/min.
⇒ Efficiency of faster pipe = units/minute
Let the total work to be done be 140 units.
⇒ Efficiency of both pipes = = 7 units/min
Now, x + = 7
⇒ 7x = 14
⇒ x = 2
Efficiency of faster pipe =
⇒ = 5 units/min
Time taken by faster pipe to fill the tank = = 28 minutes
Hence the faster pipe alone can fill the tank in 28 min.