There are three taps of diameter 2 cm, 3 cm and 4 cm, respectively. The ratio of the water flowing through them is equal to the ratio of the square of their diameters. The biggest tap can fill an empty tank alone in 81 min. If all the taps are opened simultaneously, then how long will the tank take (in min) to be filled?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e.
Given that
There are three taps A, B, and C of diameter 2 cm, 3 cm, and 4 cm, respectively.
The ratio of the water flowing through them is equal to the ratio of the square of their diameters
According to the question
Now, the efficiency of taps A, B, and C = 4, 9, and 16 respectively
Total Capacity (work) = 81 × 16 = 1296 min
If all the taps are opened simultaneously then tank fill in = 1296/(4 + 9 + 16)
= 1296/29 = min