There are three bottles of mixture of syrup and water of ratios 2:3, 3:4 and 7:5. 10 Litres of first and 21 Litres of second bottles are taken. How much quantity from third bottle is to be taken so that final mixture from three bottles will be of ratios 1:1.
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 30
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Understanding |
Application |
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Ratio of quantities of syrup and water in 1st bottle = 2 : 3 And 10 litres of 1st bottle is taken. |
So, Quantity of syrup taken from 1st bottle = 10 × 2/5 = 4 litres And Quantity of water taken from 1st bottle = 10 × 3/5 = 6 litres |
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Ratio of quantities of syrup and water in 2nd bottle = 3 : 4 And 21 litres of 2nd bottle is taken. |
So, Quantity of syrup taken from 2nd bottle = 21 × 3/7 = 9 litres And Quantity of water taken from 2nd bottle = 21 × 4/7 = 12 litres |
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Ratio of quantities of syrup and water in 3rd bottle = 7 : 5 And Suppose x litres of 3rd bottle is taken. |
So, Quantity of syrup taken from 3rd bottle = x × 7/12 = 7x/12 litres And Quantity of water taken from 3rd bottle = x × 5/12 = 5x/12 litres |
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The ratio of syrup and water should be 1 : 1 when we mix the mixtures from 3 bottles. |
So, (4 + 9 + 7x/12) = (6 + 12 + 5x/12) 2x/12 = 5 x = 30 Hence, 30 litres from third bottle is to be taken. |