SSC CHSL 2020 PYQ — Question 60

SSC CHSL - 18th October 2020 - Shift 1 • Quantitative Aptitude • Q60

 , then the value of cot A is:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 2.

Understanding/Application

(1 - tan A)/(1 + tan A) = (tan3 + tan15 + tan30 + tan75 + tan87)/(tan27 + tan39 + tan51 + tan60 + tan63)

(1 - tan A)/(1 + tan A) = (tan3 + tan15 + tan30 + tan(90 -15) + tan(90 - 3))/(tan27 + tan39 + tan(90 -39) + tan60 + tan(90 - 27))

(1 - tan A)/(1 + tan A) = (tan3 + tan15 + tan30 + cot15 + cot3)/(tan27 + tan39 + cot39 + tan60 + cot27)

(1 - tan A)/(1 + tan A) = tan30/tan60

(1 - tan A)/(1 + tan A) = 1/3

3 - 3tan A = 1 + tan A

4 tan A = 2

tan A = 1/2

cot A = 2