The width of a rectangle is such that its length exceeds it by 2 cm. Given that the perimeter measures 44 cm, determine the area of the rectangle.
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Correct answer: D
Explanation
Given:
Width of rectangle = x cm
Length of rectangle = (x + 2) cm
Perimeter = 44 cm
By formula:
Perimeter of rectangle = 2(l + b)
Area of rectangle = l × b
2(l + b) = 44
2[(x + 2) + x] = 44
2(2x + 2) = 44
4x + 4 = 44
4x = 40
x = 10
Width = 10 cm
Length = 12 cm
Area = 12 × 10 = 120 cm²