The volume of the water in two tanks, A and B, is in the ratio of 6 : 5. The volume of water in tank A is increased by 30%. By what percentage should the volume of water in tank B be increased so that both the tanks have the same volume of water?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e 56%.
| Understanding/Application |
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Let the common ratio be x. Volume of water in tank A after increasing 30% = 130(6x)/100 = 7.8x The volume of water to be increased in tank B to have the same volume as tank A = 7.8x - 5x = 2.8x |
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Percentage increase in the volume of water in tank B = 2.8x(100)/5x = 56% |