SSC MTS 2022 PYQ — Question 71

The correct answer is option 2 i.e. 36 cm.

Volume of cone $= {1 \over 3} \pi r^2 h$

Area of circular base = πr²

Volume of cone = 1848 cm³

Area of base = 154 cm²

Now, πr²= 154

⇒22/7 × r² = 154

⇒ r² = 49

⇒ r = 7

Now using the formula for the volume of the cone,

Volume of cone $= {1 \over 3}\pi r^2 h$

⇒1/3 × 22/7 × 7² × h = 1848

⇒ h = (1848 × 3)/(22 × 7)

⇒ h = 36

Hence the required height of the cone is 36 cm.