The value of the expression 2(sin6θ + cos6θ) – 3(sin4θ + cos4θ) + 1 is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 0
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Application |
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2(sin6θ + cos6θ) – 3(sin6θ + cos6θ) + 1 Put θ = 0° ⇒ 2(0 + 1) – 3(0 + 1) + 1 ⇒ 2 – 3 + 1 ⇒ 0 |