The value of (tan30ocosec60o + tan60osec30o)/(sin230o + 4cot245o - sec260o) is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e 32/3.
| Understanding/Application |
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= (tan300 cosec600 + tan600sec300)/(sin2300 + 4cot2450 - sec2600) Putting the values - = (1/ × 2/ + × 2/)/(1/22 + 4 × 1 - 22) |
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= (2/3 + 2)/(1/4 + 4 - 4) = (8/3)/(1/4) = 32/3 |