The value of (Sin30oCos60o + Cos45oSin45o)/(tan60oCot30o) is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e 1/4.
| Understanding/Application |
| (Sin300Cos600 + Cos450Sin450)/(tan600Cot300) |
|
[(1/2 × 1/2) + (√1/√2 × 1/√2)]/(√3 × √3) = [1/4 + 1/2]/3 = (3/4)/3 = 3/12 = 1/4 |