SSC CHSL 2023 PYQ — Question 58

The correct answer is option 1 i.e. 2.

$\frac{sin 58°}{ cos32°} + \frac{sin55° sec35°}{ tan5° tan 45 °tan85°}$

We know that,

sin(90 - A) = cosA

and, tan(90 - A) = cotA

Now,

⇒ $\frac{cos 32°}{ cos32°} + \frac{cos55°\times {1\over cos35°}}{ tan5° tan 45 °tan(90 - 5)°}$

⇒ $1 + \frac{1}{ tan5° \times tan 45° \times cot 5°}$ [tan 45° = 1]

⇒ 1 + 1 = 2