The value of √(sec2θ + cosec2θ) × √(tan2θ - sin2θ) is equal to:
Show answer & explanation
Correct answer: B
Explanation
Correct Answer is option 2 i.e. Sinθ Sec2θ
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Understanding |
Application |
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Put θ = 45° and check with the options. |
√(sec2θ + cosec2θ) × √(tan2θ - sin2θ) θ = 45° ⇒ √(sec245° + cosec245°) × √(tan245° - sin245°) ⇒√(2 + 2) × √(1 - 1/2) ⇒ 2/√2 ⇒ √2 Checking the options by putting θ = 45: Option 2: Sin45° Sec245° = 1/√2 × 2 = √2 Hence, Option 2 is correct. |