SSC CPO 2023 PYQ — Question 101

The correct answer is option 1 i.e.  $\frac{1}{24}$

Given that

$\frac{(157\times157)+(157\times133)+(133\times133)}{(157\times157\times157)-(133\times133\times133)}$

⇒ $\frac{(157\times157)+(157\times133)+(133\times133)}{(157\times157\times157)-(133\times133\times133)}$

As we know,

⇒ a³ + b³ = (a + b) (a² – ab + b²)

⇒ $\frac{(157\times157)+(157\times133)+(133\times133)}{(157-133)((157\times157)+(157\times133)+(133\times133))}$

⇒ $\frac{1}{(157 - 133)}$

⇒ $\frac{1}{24}$