SSC CGL 2020 PYQ — Question 53

SSC CGL Tier II - Quant - 15 Nov 2020 • Quantitative Aptitude • Q53

The value of is (0.0203×2.92)/(0.7×0.0365×2.9) ÷ (12.12)2 - (8.12)2)/(0.25)2+(0.25)(19.99) :

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 0.05

Concept 

Calculation 

Identity = (a - b) ( a + b) = (a2  -  b2)

Application

{(203 × 292 × 1 / 106 )/(7 × 365 × 29 × 1 / 10 6  )} ÷ { (12.12 - 8.12) / ((0.25)2+(0.25)(19.99))}

{292/365}  ÷ {(4) x (20.24) / (0.25)(20.24)}                           

 = 0.8/16 = 0.05