The value of (Cos29oCosec61otan45o + 2Sin35oSec55o)/(3 Sin242o + 3 Sin248o) is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e 1.
| Understanding/Application |
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(Cos290Cosec610tan450 + 2Sin350Sec550)/(3 Sin2420 + 3 Sin2480) = [cos29 (1/sin61)1 + 2sin35(1/cos55)]/(3sin242 + 3(sin(90 - 42)2] = [cos29(1/sin(90 -29)) + 2sin35 (1/cos(90 - 35))]/(3sin242 + 3cos242) = [cos29(1/cos29) + 2sin35(1/sin35)]/3 |
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= (1 + 2)/3 = 3/3 = 1 |