SSC CPO 2020 PYQ — Question 123

SSC CPO - 23 Nov 2020 - Shift 2 • Quantitative Aptitude • Q123

The value of (514÷37  of  12)÷(519−778÷9920)×1121−(5÷2  of12)\left( {5\frac{1}{4} \div \frac{3}{7}\;of\;\frac{1}{2}} \right) \div \left( {5\frac{1}{9} - 7\frac{7}{8} \div 9\frac{9}{{20}}} \right) \times \frac{{11}}{{21}} - \left( {5 \div 2\;of\frac{1}{2}} \right) is :

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. -2

⇒ (514÷37  of  12)÷(519−778÷9920)×1121−(5÷2  of12)\left( {5\frac{1}{4} \div \frac{3}{7}\;of\;\frac{1}{2}} \right) \div \left( {5\frac{1}{9} - 7\frac{7}{8} \div 9\frac{9}{{20}}} \right) \times \frac{{11}}{{21}} - \left( {5 \div 2\;of\frac{1}{2}} \right)

 ⇒ (214÷37  of  12)÷(469−638÷18920)×1121−(5÷2  of12)\left( {\frac{21}{4} \div \frac{3}{7}\;of\;\frac{1}{2}} \right) \div \left( {\frac{46}{9} - \frac{63}{8} \div \frac{189}{{20}}} \right) \times \frac{{11}}{{21}} - \left( {5 \div 2\;of\frac{1}{2}} \right)

 ⇒ (214×143)÷(469−638×20189)×1121−5\left( {\frac{21}{4} \times \frac{14}{3}} \right) \div \left( {\frac{46}{9} - \frac{63}{8} \times \frac{20}{{189}}} \right) \times \frac{{11}}{{21}} - 5

 ⇒ (492)÷(469−56)×1121−5(\frac{49}{2})\div(\frac{46}{9}-\frac{5}{6})\times\frac{11}{21}-5

 ⇒ 492×36154×1121−5\frac{49}{2}\times\frac{36}{154}\times\frac{11}{21}-5

 ⇒ 3 - 5

 ⇒ - 2