The value of 54×223÷59 of 115+225×416÷27 of 213\frac{5}{4} \times 2\frac{2}{3} \div \frac{5}{9}\;of\;\;1\frac{1}{5} + \frac{2}{{25}} \times 4\frac{1}{6} \div \frac{2}{7}\;of\;2\frac{1}{3}45×232÷95of151+252×461÷72of231 is: A112\frac{1}{2}21 B2 12\frac{1}{2}21 C5 12\frac{1}{2}21 D3 12\frac{1}{2}21 Show answer & explanationCorrect answer: CExplanationThe correct answer is option 3 i.e. 5 12\frac{1}{2}21 54×223÷59 of 115+225×416÷27 of 213\frac{5}{4} \times 2\frac{2}{3} \div \frac{5}{9}\;of\;\;1\frac{1}{5} + \frac{2}{{25}} \times 4\frac{1}{6} \div \frac{2}{7}\;of\;2\frac{1}{3}45×232÷95of151+252×461÷72of231 = 54×83÷59 of 65+225×256÷27 of 73\frac{5}{4} \times \frac{8}{3} \div \frac{5}{9}\;of\;\;\frac{6}{5} + \frac{2}{{25}} \times \frac{25}{6} \div \frac{2}{7}\;of\;\frac{7}{3}45×38÷95of56+252×625÷72of37 =54×83×95 × 65+225×256×72 × 73\frac{5}{4} \times \frac{8}{3} \times \frac{9}{5}\ \times \;\frac{6}{5} + \frac{2}{{25}} \times \frac{25}{6} \times \frac{7}{2}\ \times \;\frac{7}{3}45×38×59 ×56+252×625×27 ×37 = 5 12\frac{1}{2}21