SSC GD 2025 PYQ — Question 58

SSC GD Const 2025 (English) - 12 Feb 2025 - Shift 3 • Quantitative Aptitude • Q58

The value of 40 - 3 × [10 + 6 × {20 - 10 (6 - 5) × 2} ÷ 47] is:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 10.

40 - 3 × [10 + 6 × {20 - 10 (6 - 5) × 2} ÷ 47]

⇒ 40 - 3 × [10 + 6 × {20 - 10 × 1 × 2} ÷ 47]

⇒ 40 - 3 × [10 + 6 × 0 ÷ 47]

⇒ 40 - 3 × [10 + 0]

⇒ 40 - 30 = 10