SSC CGL 2020 PYQ — Question 48

SSC CGL Tier II - Quant - 16 Nov 2020 • Quantitative Aptitude • Q48

The value of 4 ÷ 12 of [3 ÷ 4 of {(4 - 2) × 6 ÷ 2}] - 2 × 6 ÷ 8 + 3 is:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 416\frac{1}{6}.

⇒ 4 ÷ 12 of [3 ÷ 4 of {(4 - 2) × 6 ÷ 2}] - 2 × 6 ÷ 8 + 3

⇒ 4 ÷ 12 of [3 ÷ 24] - 2 × 6 ÷ 8 + 3

⇒ 4 ÷ 3/2 - 2 × 6 ÷ 8 + 3

⇒ 8/3 - 6/4 + 3

⇒ 50/12 = 25/6.