The correct answer is Option 4 i.e. 2459
Concept USed:
cos(90 - A) = sinA
sec(90 - A) = cosecA
Explanation:
According to the given question,
(cos15°+sin75°)(sec15°+cosec75°)3tan260°+sec230°−sin245°
Putting the values of tan60°, sec30° and sin45°, we get
⇒(cos(90°−75°)+sin75°)(sec(90°−75°)+cosec75°)3(3)2+(32)2−(21)2
Now, (sin75°+sin75°)(cosec75°+cosec75°)9+34−21
⇒ (2×sin75°)(2×cosec75°)659
⇒ 4659
⇒ 2459
Hence the required answer is 2459.