The value of (3(cot² 47⁰ - sec² 43⁰) 43⁰ - 2(tan² 23⁰ -cosec² 67⁰))/(cosec² (68⁰ + θ)-tan(θ+61⁰)-tan²(22⁰-θ)+cot(29⁰-θ)) is:

The value of (3(cot² 47⁰ - sec² 43⁰) 43⁰ - 2(tan² 23⁰…

The value of $\frac{3(cot^2 47^0 - sec^2 43^0) 43^0 - 2(tan^2 23^0 -cosec^2 67^0)}{cosec^2 (68^0 + \theta)-tan(\theta+61^0)-tan^2(22^0-\theta)+cot(29^0-\theta)}$ is:

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Correct answer: A

Explanation

The correct answer is option 1 i.e. -1

[3( tan²43 - sec²43) - 2(cot²67 - cosec²67)]/[cosec²(68 + $\theta$ ) - tan( $\theta$ + 61) - cot²(68 + $\theta$ ) + tan( $\theta$ + 61)

= (-3 + 2)/(1 - 0)

= -1/1 = - 1.

SSC CGL 2022 PYQ — Question 34