The value of 27 + [3(50 – 20) + 168 ÷ 4 + 2 – 11 × 2] is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e 139
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Understanding Tricks |
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Application Using BODMAS rule 27 + [3(50 – 20) + 168 ÷ 4 + 2 – 11 × 2] 27 + [3(30) + 168 ÷ 4 + 2 – 11 × 2] 27 + [90 + 168 ÷ 4 + 2 – 11 × 2] 27 + [90 + 42 + 2 – 11 × 2] 27 + [90 + 42 + 2 - 22] 27 + [90 + 42 - 20] 27 + 112 139 |