The value of (267 of 415÷23)×119÷(34×223 of 12)÷14)(2\dfrac{6}{7} \ \text{of} \ 4\dfrac{1}{5} \div \dfrac{2}{3}) \times 1\dfrac{1}{9}\div (\dfrac{3}{4} \times 2\dfrac{2}{3} \ \text{of} \ \dfrac{1}{2}) \div \dfrac{1}{4})(276 of 451÷32)×191÷(43×232 of 21)÷41) is? A5 B8 C1/8 D1/5 Show answer & explanationCorrect answer: AExplanationThe correct answer is option 1 i.e. 5. ⇒ (267 of 415÷23)×119÷(34×223 of 12)÷14)(2\dfrac{6}{7} \ \text{of} \ 4\dfrac{1}{5} \div \dfrac{2}{3}) \times 1\dfrac{1}{9}\div (\dfrac{3}{4} \times 2\dfrac{2}{3} \ \text{of} \ \dfrac{1}{2}) \div \dfrac{1}{4})(276 of 451÷32)×191÷(43×232 of 21)÷41) ⇒ (207 of 215÷23)×109÷(34×83 of 12)÷14)(\dfrac{20}{7} \ \text{of} \ \dfrac{21}{5} \div \dfrac{2}{3}) \times \dfrac{10}{9}\div (\dfrac{3}{4} \times \dfrac{8}{3} \ \text{of} \ \dfrac{1}{2}) \div \dfrac{1}{4})(720 of 521÷32)×910÷(43×38 of 21)÷41) ⇒ (12÷23)×109÷(34×43)÷14)(12 \div \dfrac{2}{3}) \times \dfrac{10}{9}\div (\dfrac{3}{4} \times \dfrac{4}{3}) \div \dfrac{1}{4})(12÷32)×910÷(43×34)÷41) ⇒ (18×109÷1÷14)(18 \times \dfrac{10}{9}\div 1 \div \dfrac{1}{4})(18×910÷1÷41) ⇒ 18×103618 \times\dfrac{10}{36}18×3610 = 5