SSC CGL 2019 PYQ — Question 84

SSC CGL Tier II Quant - 11/09/2019 • Quantitative Aptitude • Q84

The value of (267 of 415÷23)×119÷(34×223 of 12)÷14)(2\dfrac{6}{7} \ \text{of} \ 4\dfrac{1}{5} \div \dfrac{2}{3}) \times 1\dfrac{1}{9}\div (\dfrac{3}{4} \times 2\dfrac{2}{3} \ \text{of} \ \dfrac{1}{2}) \div \dfrac{1}{4}) is?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 5.

⇒ (267 of 415÷23)×119÷(34×223 of 12)÷14)(2\dfrac{6}{7} \ \text{of} \ 4\dfrac{1}{5} \div \dfrac{2}{3}) \times 1\dfrac{1}{9}\div (\dfrac{3}{4} \times 2\dfrac{2}{3} \ \text{of} \ \dfrac{1}{2}) \div \dfrac{1}{4})

⇒ (207 of 215÷23)×109÷(34×83 of 12)÷14)(\dfrac{20}{7} \ \text{of} \ \dfrac{21}{5} \div \dfrac{2}{3}) \times \dfrac{10}{9}\div (\dfrac{3}{4} \times \dfrac{8}{3} \ \text{of} \ \dfrac{1}{2}) \div \dfrac{1}{4})

⇒ (12÷23)×109÷(34×43)÷14)(12 \div \dfrac{2}{3}) \times \dfrac{10}{9}\div (\dfrac{3}{4} \times \dfrac{4}{3}) \div \dfrac{1}{4})

⇒ (18×109÷1÷14)(18 \times \dfrac{10}{9}\div 1 \div \dfrac{1}{4})

⇒ 18×103618 \times\dfrac{10}{36} = 5