SSC CGL 2022 PYQ — Question 52

SSC CGL - 20 April 2022 - Shift 2 • Quantitative Aptitude • Q52

The value of 

25 ÷ 10 - (74\frac{7}{4}×13\frac{1}{3}) of 65\frac{6}{5}+143\frac{14}{3}×910\frac{9}{10}+(15\frac{1}{5}÷125\frac{1}{25}) is:

Show answer & explanation

Correct answer: D

Explanation

 The correct answer is option 4 i.e. 11

Explanation:

From the given question,

25 ÷ 10 - (74\frac{7}{4}×13\frac{1}{3}) of 65\frac{6}{5}+143\frac{14}{3}×910\frac{9}{10}+(15\frac{1}{5}÷125\frac{1}{25})

⇒ 2.5−712×65+215+52.5 - {7\over 12} × {6\over 5} + {21\over 5} + 5

⇒ 2.5−710+215+52.5 - {7\over 10} + {21\over 5} + 5

Taking the LCM of the denominator,

⇒ (25−7+42+50)10{(25 - 7 + 42 + 50)\over 10}

⇒ 11010{110\over 10} = 11

Hence the value of 25 ÷ 10 - (74\frac{7}{4}×13\frac{1}{3}) of 65\frac{6}{5}+143\frac{14}{3}×910\frac{9}{10}+(15\frac{1}{5}÷125\frac{1}{25}) is 11.