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SSC CPO 2020 PYQ — Question 102

SSC CPO - 25 Nov 2020 - Shift 2 • Quantitative Aptitude • Q102

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The value of 23\frac{2}{3}÷ 310\frac{3}{10} of 49\frac{4}{9} - 45\frac{4}{5} × 119\frac{1}{9} ÷815\frac{8}{15} + 34\frac{3}{4} ÷ 12\frac{1}{2} is :

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Correct answer: B

Explanation

The correct answer is Option 2 i.e. ​​296\frac{29}{6}.

23\frac{2}{3} ÷ 310\frac{3}{10} of 49\frac{4}{9} - 45\frac{4}{5} × 119\frac{1}{9} ÷ 815\frac{8}{15} + 34\frac{3}{4} ÷ 12\frac{1}{2}

Applying BODMAS

⇒ 23\frac{2}{3} ÷ 215\frac{2}{15} - 45\frac{4}{5} × 109\frac{10}{9} ÷ 815\frac{8}{15} + 34\frac{3}{4} ÷ 12\frac{1}{2}

⇒ 23\frac{2}{3} × 152\frac{15}{2} - 45\frac{4}{5} × 109\frac{10}{9} × 158\frac{15}{8} + 34\frac{3}{4} × 2

⇒ 23\frac{2}{3} × 152\frac{15}{2} - 45\frac{4}{5} × 109\frac{10}{9} × 158\frac{15}{8} + 34\frac{3}{4} × 2

⇒ 5 - 89\frac{8}{9} × 158\frac{15}{8} + 32\frac{3}{2}

⇒ 5 - 53\frac{5}{3} + 32\frac{3}{2}

⇒ (30 - 10 + 9)/6

⇒ 296\frac{29}{6}