SSC CPO 2024 PYQ — Question 150

SSC CPO - 29 June 2024 Shift 2 • Quantitative Aptitude • Q150

The value of 122 + 123 ÷ (12 + 12 ÷ 1) + 313 ÷ 52 × 34 ÷ 623 × 76{1\over{2}^2}\ +\ {1\over{2}^3}\ ÷\ {({1\over2}\ +\ {1\over2}\ ÷\ 1)}\ +\ {3{1\over3}}\ ÷\ {5\over2}\ ×\ {3\over4}\ ÷\ {6{2\over3}}\ ×\ {7\over6} is:

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Correct answer: C

Explanation

The correct answer is option 3 i.e. 112011\over20.

According to the given question,

122 + 123 ÷ (12 + 12 ÷ 1) + 313 ÷ 52 × 34 ÷ 623 × 76{1\over{2}^2}\ +\ {1\over{2}^3}\ ÷\ {({1\over2}\ +\ {1\over2}\ ÷\ 1)}\ +\ {3{1\over3}}\ ÷\ {5\over2}\ ×\ {3\over4}\ ÷\ {6{2\over3}}\ ×\ {7\over6}

⇒ 14 + 18 ÷ 1 + 103 ÷ 52 × 34 ÷ 203 × 76{1\over4}\ +\ {1\over8}\ ÷\ {1}\ +\ {{10\over3}}\ ÷\ {5\over2}\ ×\ {3\over4}\ ÷\ {{20\over3}}\ ×\ {7\over6}

⇒ 14 + 18 + 43 × 980  × 76{1\over4}\ +\ {1\over8}\ +\ {{4\over3}}\ ×\ {9 \over 80}\ \ ×\ {7\over6}

⇒ 14 + 18 + 740{1\over4}\ +\ {1\over8}\ +\ {7 \over 40}

⇒ 10+5+740{10 + 5 + 7}\over 40 

⇒ 224022 \over 40 = 112011\over20

Hence the required answer is 112011\over20.