The correct answer is Option 2 i.e. cosec A + cot A.
Concept USed:
sin2A=1−cos2A
1/sinA = cosecA
cosA/sinA = cotA
Explanation:
Multiplying (1 + cosA) in both numerator and denominator of 1−cosA1+cosA ,
we get
⇒ (1−cosA)(1+cosA)(1+cosA)(1+cosA) = 1−cos2A(1+cosA)2 = sin2A(1+cosA)2
Removing square root, sinA(1+cosA) = sinA1+sinAcosA = cosecA + cotA.
Hence the value of1−cosA1+cosA = cosecA + cotA.