SarkariPYQ

SSC Selection Post 2020 PYQ — Question 51

SSC Selection Post - Matriculation Level 2020 - 6 Nov 2020 - Shift 1 • Quantitative Aptitude • Q51

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The value of 0.325×0.325+0.175×0.175−25×0.004555×0.0065×0.325−7×0.175×0.0250.325×0.325+0.175×0.175−25×0.00455\over5×0.0065×0.325−7×0.175×0.025 is:

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Correct answer: D

Explanation

The correct answer is option 4 i.e. 0.3.

⇒ 0.325×0.325+0.175×0.175−25×0.004555×0.0065×0.325−7×0.175×0.0250.325×0.325+0.175×0.175−25×0.00455\over5×0.0065×0.325−7×0.175×0.025

⇒ (0.325)2+(0.175)2−2×0.325×0.1755×0.0065×3.25−7×0.175×0.025(0.325)^2+(0.175)^2−2×0.325×0.175\over5×0.0065×3.25−7×0.175×0.025

⇒ (0.325−0.175)20.325×0.325−0.175×0.175(0.325-0.175)^2\over0.325×0.325−0.175×0.175

⇒ (0.325−0.175)2(0.325)2−(0.175)2(0.325-0.175)^2\over(0.325)^2−(0.175)^2

⇒ (0.325−0.175)2(0.325−0.175)(0.325+0.175)(0.325-0.175)^2\over(0.325−0.175)(0.325+0.175)

⇒ (0.325−0.175)(0.325+0.175)(0.325-0.175)\over(0.325+0.175) = 0.150.50.15\over0.5 = 0.3