The upper part of a tree broken over by the wind make an angle of 60o with the ground. The distance between the root and the point where top of the tree touches the ground is 25 metres. What was the height (in metres) of the tree?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2, i.e. 93.3
In △BCD
cos60o = CD/BD
1/2 = 25/BD
BD = 50
tan60o = BC/CD
√3 = BC/25
BC = 25√3 m
Height= BC + BD = 50+25√3 = 93.3