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SSC CGL 2022 PYQ — Question 57

SSC CGL Tier II - Quant - 29 Jan 2022 • Quantitative Aptitude • Q57

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The total surface area of a cylinder is 4092cm2 and the diameter of its base is 21 cm. What is 50% volume (in cm3) of the cylinder (nearest to an integer)?

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Correct answer: A

Explanation

The correct answer is option 1 i.e. 8922

2πr(h+r)2\pi r(h+r) = 4092

Diameter = 21

Radius = 21/2

2 × 22/7 × 21/2 (h + 21/2) = 4092

h + 21/2 = 62

h = 51.5

50% of volume of cylinder = 1/2 × πr2h\pi r^2h = 1/2 × 22/7 × 10.5 × 10.5 × 51.5 = 8922.375

= 8922.