SSC CHSL 2022 PYQ — Question 54

SSC CHSL - 30 May 2022 - Shift 2 • Quantitative Aptitude • Q54

The total surface area of a cuboid of length 90 cm, breadth 50 cm and height 4 m is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 12.1 m2

Given: 

Length = 90 cm = 90/100 = 0.9 m

Breadth = 50 cm = 50/100 = 0.5 m

Height = 4m 

Concept Used:

Total surface are of cuboid = 2(lb + bh + hl)    ....(i)

Explanation:

According to the given question,

Total surface area of cuboid = 2(0.9 × 0.5 + 0.5 × 4 + 4 × 0.9)   {using equation (i)}

⇒ TSA = 2( 0.45 + 2.0 + 3.6)

⇒ TSA = 2 × 6.05

⇒ TSA = 12.1

Hence the required total surface area of cuboid is 12.1 m2.