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SSC Selection Post 2024 PYQ — Question 57

SSC Selection Post - Graduation Level - 24 June 2024 - Shift 3 • Quantitative Aptitude • Q57

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The surface area ( in cm2 ) of a sphere, whoese diameter is 42 cm is : ( take π=227\pi = \frac{22}{7}  )

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Correct answer: B

Explanation

The correct answer is option 2 i.e. 5544.

Radius (r) = 42/2 = 21 cm

Total surface area = 4πr2 = 4 × (22/7) × (21)2 = 5544 cm2