The sum of the first 13 terms of a GP is equal to the sum of the first 11 terms in the same GP. The sum of the first 15 terms is 1200. What is the 21st term in the same GP?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 1200.
S13 = S11
⇒ a(1 - r13)/(1 - r) = a(1 - r11)/(1 - r)
⇒ r13 = r11
⇒ r2 = 1
⇒ r = - 1
So, S15 = 1200
⇒ a[1 - (- 1)15]/[1 - (- 1)] = 1200
⇒ a(1 + 1)/2 = 1200
⇒ a = 1200
T21 = ar20 = 1200 × (- 1)20 = 1200