The sum of five consecutive multiples of 7 is 455. What is the largest number in this series?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 105.
Let the five consecutive multiples of 7 be 7a, 7a + 7, 7a + 14, 7a + 21, and 7a + 28.
According to the question;
7a + 7a + 7 + 7a + 14 + 7a + 21 + 7a + 28 = 455
35a + 70 = 455
35a = 385
a = 11
Numbers are 77, 84, 91, 98, and 105.
The largest number in the series is 105.