The sum of 3-digit numbers abc,cab and bca is not divisible by :
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 31
abc = 100a + 10b + c.................(1)
cab = 100c + 10a + b................(2)
bca = 100b + 10c + a................(3)
On adding all equations we get,
111a + 111b + 111c
= 111(a + b + c)
= 3 × 37 × (a + b + c).
So one can say that the number must be divisible by 3, 37 and (a + b + c).