SSC CPO 2023 PYQ — Question 147

SSC CPO - 04 Oct 2023 - Shift 1 • Quantitative Aptitude • Q147

The square root of (14)×(19)×(125)×(149)÷(36121)(\frac{1}{4})\times (\frac{1}{9})\times(\frac{1}{25})\times(\frac{1}{49})\div(\frac{36}{121})

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 111260\frac{11}{1260}

Given that

 The square root of (14)×(19)×(125)×(149)÷(36121)(\frac{1}{4})\times (\frac{1}{9})\times(\frac{1}{25})\times(\frac{1}{49})\div(\frac{36}{121})

⇒ (14)×(19)×(125)×(149)÷(36121)\sqrt (\frac{1}{4})\times (\frac{1}{9})\times(\frac{1}{25})\times(\frac{1}{49})\div(\frac{36}{121})

⇒ (1900)×(149)×(12136) \sqrt (\frac{1}{900})\times(\frac{1}{49})\times(\frac{121}{36})

⇒  111260\frac{11}{1260}