The smallest number which when divided by 8 and 14 leaves remainders 5 and 11, respectively is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 53
Calculations:
LCM of 8 and 14 = 56
Number to be subtracted from 56 = 8 - 5 = 14 - 11 = 3
Required number = 56 - 3 = 53