SSC CGL 2017 PYQ — Question 4

SSC CGL Tier II Quant - 12/01/2017 • Quantitative Aptitude • Q4

The smallest number, which should be added to 756896 so as to obtain a multiple of 11, is _____.

Show answer & explanation

Correct answer: C

Explanation

  The correct answer is option 3 i.e. 3

Understanding

Application

The remainder must be obtained when 756896 is divided by 11.

So,

Remainder when 756896 is divided by 11 = 8

We know,

11 – 8 = 3

Hence,

3 must be added in the given number so that the number becomes divisible by 11.