The smallest number exactly divisible by 104, 78, and 260 is P. If P + 40 = Q2, then what is the positive value of Q?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 40.
We know that,
The smallest number that is divisible by the given numbers is the lowest common multiple (LCM) of those numbers
According to the given question,
LCM (104, 78, and 260) = 1560
So, the value of P = 1560
Now, the value of the given expression,
P + 40 = Q2
⇒ 1560 + 40 = Q2
⇒ Q2 = 1600
⇒ Q = 40
Hence, the required answer is Q = 40