SSC GD 2025 PYQ — Question 41

SSC GD Const 2025 (English) - 13 Feb 2025 - Shift 2 • Quantitative Aptitude • Q41

The smallest natural number which is divisible by 5, 10, 49 and 28 is:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is Option 3 i.e. 980.

LCM = product of highest powers of prime factors

LCM of 5, 10, 49 and 28 = 980