SSC CGL 2023 PYQ — Question 51

The correct answer is option 2 i.e. ₹37,500.

Let the principal amount be P.

SI = $\frac{P × R × T}{100}$

T = 6 years     

R = 4

SI₁ = $\frac{P × 4 × 6}{100}$ = 24P/100 ​= 0.24P

Simple Interest for 11 years at 4% per annum

SI₂​ = $\frac{P × 4 × 11}{100}$= 44P/100 = 0.44P

the difference between the two simple interests is ₹7,500, so:

⇒ SI_2​ − SI₁​ = 7500

⇒ 0.44P − 0.24P = 7500

⇒ 0.20P = 7500

⇒ P = 7500/0.20 ​= ₹ 37500