SSC CHSL 2023 PYQ — Question 71

The correct answer is option 2 i.e.  $52\frac{1}{2}$ cm².

(20, 21, 29) is a Pythagorean triplet. So, the given triangle is a right-angle triangle.

Hypotenuse = 29; Base = 20; Height = 21

Area of the original triangle = (1/2) × Base × Height = (1/2) × 20 × 21 = 210 cm²

By joining the midpoints of the sides of a triangle, we get four congruent triangles.

Area of the triangle formed by joining the midpoints = (1/4) × 210 = $52\frac{1}{2}$ cm²

Therefore, the area of the required triangle is $52\frac{1}{2}$ cm².