The sides AB, BC and AC of a ΔABC are 12 cm, 8 cm and 10 cm respectively. A circle is inscribed in the triangle touching AB, BC and AC at D, E and F, respectively. The difference between the lengths of AD and CE is:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 4 cm
| Understanding/Application |
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Given: AB = 12 cm BC = 8 cm CA = 10 cm Let AD = AB/2 = 12/2 = 6 cm In such type DB = AB - AD = 12 - 6 = 6 cm here, BD = BE due to tangent on same circle with same point. So, BE = 6 cm. and, CE = BC = BE = 8 - 6 = 2 cm Hence, the difference between the lengths of AD and CE = 6 - 2 = 4 cm |