The sides AB and AC of ΔABC are produced to points D and E, respectively. The bisectors of ∠CBD and ∠BCE meet at P. If ∠A = 72°, then the measure of ∠P is?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 54°
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Concept |
Understanding |
Application |
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Angle at ex-centre = 90° – (Opposite angle)/2 |
Given ∠A = 72°
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Since bisectors of ∠CBD and ∠BCE meet at P: P is the ex-centre of ∆ABC. ∠BPC = 90 – A/2 = 90 – 72/2 = 90 – 36 = 54° |