The ratio of the sum, difference, and product of two numbers is 11: 1: 120. What is the sum of their squares?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 976.
Let numbers = x and y
(x + y) + (x - y) = 11k + k ⇒ x = 6k
(x + y) - (x - y) = 11k - k ⇒ y = 5k
xy = 120k
⇒ (6k)(5k) = 120k
⇒ k = 4
x = 6k = 24, y = 5k = 20
x2 + y2 = 242 + 202 = 576 + 400 = 976