SSC CPO 2024 PYQ — Question 121

SSC CPO - 29 June 2024 - Shift 3 • Quantitative Aptitude • Q121

The ratio of the speed of a boat to that of the current water is 35 : 8. The boat goes along with the current in 5 hours 10 minutes. What will be the time taken by the boat to come back?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 8 hours 13 minutes 48 seconds.

Let's denote the speed of the boat in still water as B and the speed of the current as C.

Given, B:C = 35:8

We can assume B = 35x and C = 8x, where x is a constant.

⇒ Downstream Speed (with the current): B + C = 35x + 8x = 43x

⇒ Upstream Speed (against the current): B - C = 35x - 8x = 27x

Given: Time taken to go downstream = 5 hours 10 minutes = 31/6 hours

⇒ Distance covered downstream: Distance = Speed × Time = 43x × (31/6)

To find the time taken to go upstream:

⇒ Time = Distance / Speed = (43x × 31/6) / 27x

⇒ Time = (43 × 31) / (6 × 27) = 1333 / 162 hours

Converting this to hours and minutes:

⇒ 1333 / 162 = 8 hours + (37/162) hours

Approximating (37/162) hours to the nearest minute:

⇒ (37/162) × 60 ≈ 14 minutes

Therefore, the time taken by the boat to come back (upstream) is approximately 8 hours 14 minutes.