The radius of curvature of a charged particle's passage in a homogeneous magnetic field is proportional to:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. Momentum of particle.
The radius of curvature of a charged particle's path in a homogeneous magnetic field is proportional to the momentum of the particle. This can be expressed by the formula:
r = mv/qB
Where:
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r is the radius of curvature,
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m is the mass of the particle,
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v is its velocity,
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q is the charge of the particle,
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B is the magnetic field strength.
Thus, the radius increases with higher momentum and decreases with stronger magnetic fields.