SSC CHSL 2022 PYQ — Question 72

SSC CHSL - 31 May 2022 - Shift 3 • Quantitative Aptitude • Q72

The population of a city increases 5% annually in compounded manner (yearly compounding). The present population of this city is 93051. The population of this city 2 years ago was:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 84400

Given:

Present population = 93051

Percentage increase = 5% per year

Formula Used:

Initial Population×(1+r100)T=Current PopulationInitial\ Population \times {(1 + {r \over 100})^T} = Current\ Population

Explanation:

According to the given question,

Let the population before 2 years be x.

Now, x×(1+5100)2=93051x \times {(1 + {5 \over 100})^2} = 93051 

⇒ x = 93051×40044193051 \times 400 \over 441 = 84400

Hence the required answer is 84400.